**Example:** A Yo-Yo is a uniform disk with mass m = 0.24 kg, outer radius R = 0.12 m, and inner radius r = 0.08 m. A string is wrapped around the inner ring. The string hangs from the ceiling and the Yo-Yo falls under the influence of it own weight.

a) The Yo-Yo starts to fall from rest. After the Yo-Yo falls from the height h = 0.20 m, it travels with the speed v = 0.6 m/s. Find the angular velocity and acceleration at that instant rotational dynamics:

b) Find the moment of inertia of the Yo-Yo.

c) Find the tension in the string.

**Solution**: We have for the angular speed,

**ω = v/r = 0.6m/s / 0.08m = 7.5 rad/s **

We have the angular displacement Δθ = h/r = 0.20 m/0.08 m = 2.5 rad. Since ω_{0} = 0, the angular acceleration is

The gravitational energy is transformed into kinetic energy for translation and rotation. The translational kinetic energy is

**KE _{trans} = ½ 0.24 kg (0.6 m/s)^{2} = 0.04 J. **

Thus, the rotational kinetic energy is

**KE _{rot} = PE— KE_{trans} = 0.47J – 0.04J = 0.43J= ½ I • ω^{2},**

and

**I = (2 • KE _{rot} / ω^{2}) = 2 • 0.43J / (7.5 rad/s)^{2} = 1.53 x 10-2 kg • m2.**

We have the torque exerted on the Yo-Yo,

**τ = Iα = 1.53 x 10 ^{-2} kg m^{2} • 11.25 rad/s^{2} ** = 0.17 N m

For the tension T,

**τ = Tr → T = τ/r = 0.17Nm / 0.08 m = 2.2 N.**