**Question: The mass of a woman wearing a shoe is 50kg. The area of the bottom of the shoe is 200 cm ^{2}. Find the pressure.**

Given, mass, m = 50kg

force, F = w = mg = 50 kg x 9.8 ms^{-2} = 490N

Area of the bottom of the shoe, A = 200 cm^{2} = 200 x 10^{-4} m^{2}

We know, **Pressure, P = F/A = W/A **

Then, [490 N / 200 x 10^{-4} m^{2}]

= 2.45 x 10^{4} Pa

**Note:** If we divide the unit of force by the unit of area, we get the unit of pressure. Therefore the unit of pressure is Nm^{-2}. It is called pascal (Pa).

**1 Pa = 1 Nm ^{-2}**

If a force of 1 N force is applied perpendicularly to an area of lin2 then the pressure generated is known as 1 Pa.

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