**Gauss’s Law to determine Electric field due to charged line of infinite length**

The electric field of an infinite line charge with a uniform linear charge density can be obtained by a using Gauss’ law. Let us consider a uniformly charged wire charged line of infinite length whose charge density or charge per unit length is λ. Let a point P at a distance r from the charge line be considered [Figure]. Electric field E at point P is to be determined.

Let us consider a Gaussian cylinder of length ‘l’ and radius ‘r’ taking the charge line as axis. Then the point P will be on the curved surface of the cylinder. The magnitude of the electric field E^{→} of all points on the curved surface is same and direction is outward along normal to the curved surface. So, at point P electric field E^{→} and field vector da^{→} are in the same direction. Hence according to Gauss’s law,

ε_{0} § E^{→}.d a^{→} = ε_{0} §Eda = λl.

or, ε_{0}E§ Eda = λl.

or, ε_{0}E (2πrl)a = λl

So, E = λ/ (2πε_{0}r)

E acts perpendicular to the normal of the two circular surfaces of Gaussian cylinder. Hence, for both the curved surfaces ε_{0}§E^{→}.d a^{→} = 0. So, the required electric field, E = λ / (2πε_{0}r).

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