Explain Diffraction with Example - QS Study
QS Study

We assume that a plane wave travels towards a wall with an opening of size D. Behind the wall, we observe wave within a cone of angle θ around the forward direction. At greater angles, the interference leads to cancellation of the wave. This phenomenonis called diffraction: loosely speaking, diffraction is the bending of waves around a corner. Diffraction originates from the interference of outgoing waves originating from the opening. It makes it possible to hear people from room to room, even if we can’t see them [also reflection on walls, floor, and ceiling plays a role].

We use dimensional analysis to find the angle of diffraction θ. The angle is dimensionless [θ] = 1, and depends on the ratio of two length scale & the wavelength λ and the diameter of the opening D. The diffraction phenomenon disappears when either the opening becomes very large or the wavelength becomes very small,

Sin θ = λ/D  [rectangular opening].

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When the opening is a cirde, the above expression must be slightly modified:

sin θ = 1.22 (λ/D) [circular opening].

The factor 1.22 cannot be derived with the tools of undergraduate physics [and mathematics].

 

Example: A loudspeaker is behind a rectangular opening that is 0.75 m wide. The opening is 18.0 m from a wall, where a person listens to the sound. The loudspeaker produces sounds with different frequencies. Use v = 343 m/s for the speed of sound in air.

a) The loudspeaker produces sound with frequency f = 6.0 kHz. Find the maximum distance from the center, where she can clearly hear the sound.

b) What is the highest frequency that the person can hear when she is standing at a distance x = 2.3 m from the center?

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Solution: We have the wavelength of the sound: λ = v/f = (343 m/s)/(6.0 x 103 s-1.) = 0.057 m. The opening has width D = 0.75 m.

This gives the diffraction angle

Sin θ = λ/D = (0.057 m /0.75 m) sin 0 = 0.076,   → θ = 4.4°.

Because the person is at a distance L = 18.0 m from the opening, the distance of the person from the center

x = L tan θ = 18.0 m • tan 4.4° = 1.38 m.

We have tan θ = x/L = (2.3 m) / (18.0 m) = 0.128 so that θ = 7.3°. This gives the shortest wavelength:

λ = D sin θ = 0.75 m • sin 7.3° = 0.095 m.

The frequency then follows

f = v/λ = (343 m / 0.095 m) = 3.6 kHz.