Describe Current Loop as a Magnetic Dipole - QS Study
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Current loop as a magnetic dipole:

Ampere found that the distribution of magnetic lines of force around a finite current carrying solenoid is similar to that produced by a bar magnet. This is evident from the fact that a compass needle when moved around these two bodies show similar deflections. After noting the close resemblance between these two, Ampere demonstrated that a simple current loop behaves like a bar magnet and put forward that all the magnetic phenomena is due to circulating electric current. This is Ampere’s hypothesis.

The magnetic induction at a point along the axis of a circular coil carrying current is

B = [μ0 nLa2 / 2(a2+x2)3/2]

The direction of this magnetic field is along the axis and is given by right hand rule. For points which are far away from the centre of the coil, x>>a, a2 is small and it is neglected. Hence for such points,

B = B = [μ0 nLa2 / 3x3]

If we consider a circular loop, n = 1, its area A = π a2

B = 0IA/2πx3] … … (1)

The magnetic induction at a point along the axial line of a short bar magnet is

B = (μ0/4π) . (2M/x3)

so, B = 0/2π) . (M/x3) … … (2)

Comparing equations (1) and (2), we find that

M = IA … … (3)

Hence a current loop is equivalent to a magnetic dipole of moment M = IA

The magnetic moment of a current loop is defined as the product of the current and the loop area. Its direction is perpendicular to the plane of the loop.